How To Create A Loop For This Dropdown Menu? March 20, 2024 Post a Comment And, would a loop be more efficient then listing them out one by one? Solution 1: If it's not more efficient, it's certainly more readable and reusable, which is far more important.<selectname="birthdayYear" ><optionvalue="0000">Year:</option><?phpfor(var$x = year(); $x >= 1900; $x--) { var$selected = ""; if($x == $birthdayYear) { $selected = " selected = 'selected'"; } echo("<option value="$x"$selected>$x</option>"); } ?></select>CopyIn short, my hair is a bird.Solution 2: Basically, you will :Deal with the 0000 specific line yourself, and then, have a for() loop from 2011 to 1900The loop could look a bit like this :for ($year=2011 ; $year>=1900 ; $year--) { echo'<option value="' . $year . '"'; if ($year == $birthdayYear) { echo'selected="selected"'; } echo'>' . $year . '</option>' . PHP_EOL; } Copy Of course, the 2011 year should probably not be hard-coded -- take a look at date() for a possible way of getting the current year.Solution 3: <selectname="birthdayYear" ><optionvalue="0000"<?phpecho$birthdayYear == '0000' ? 'selected="selected"' : ''; ?>>Year:</option><?phpfor($i=date('Y'); $i>1899; $i--) { $selected = ''; if ($birthdayYear == $i) $selected = ' selected="selected"'; print('<option value="'.$i.'"'.$selected.'>'.$i.'</option>'."\n"); } ?></select>CopyAnd, would a loop be more efficient then listing them out one by one?I don't think you have to worry about efficiency. Using a loop just looks cleaner it will be easier to maintain I think.Solution 4: for ($x=(int)date("Y"); $x>=1900; $x=$x--) { echo "<option value=\"", $x, "\"", ($birthdayYear==$x) ?" selected=\"selected\"" : "", ">", $x, "</option>" } CopyThis has the added bonus that you don't have to update it every year.Solution 5: Try this:<selectname="birthdayYear" ><?phpif($year == '0000') { echo'<option value="0000" selected="selected">0000</option>'; } else { echo'<option value="0000">0000</option>'; } for($year = intval(date('Y')); $year > 1900; $year --) { if($year == $birthdayYear) { echo'<option value="'.$year.'" selected="selected">'.$year.'</option>'; } else { echo'<option value="'.$year.'">'.$year.'</option>'; } } ?></select>Copy Share Post a Comment for "How To Create A Loop For This Dropdown Menu?" Top Question Red Border Still Appears On Inputs After Resetting An HTML 5 Form Firefox I have an HTML 5 form! Great, I'm excited! I decide to … Transparency Of A Filled Stroke In HTML5 I'm working on a doodling app in HTML5 and I would like… Pseudo Elements Breaking Justify-content: Space-between In Flexbox Layout I have three divs inside a parent div that are being spaced… Background Image Does Not Show On IPhone/iPad There is a background image on our Magento web site that ex… Background Color Change From Dropdown Using Javascript I would like to be able to change background colour by havi… Creating A Triangle Div With CSS I have recently learned how to create the appearance of a t… Force Background To Draw On Till End Of Line I've got a custom tag ab which is defined like so http:… Why Doesn't The Document.execCommand Work When I Click On A Div? Both the button and the div have the same 'onclick'… How To Obtain Only Visible Elements Inside An HTML Table Using JQuery? I have the following problem: I have a table in which each … Clear Or Reset Button I have a form and a working reset button. When i click the … December 2024 (1) November 2024 (39) October 2024 (61) September 2024 (19) August 2024 (217) July 2024 (200) June 2024 (422) May 2024 (699) April 2024 (464) March 2024 (830) February 2024 (916) January 2024 (805) December 2023 (842) November 2023 (354) October 2023 (581) September 2023 (334) August 2023 (341) July 2023 (260) June 2023 (330) May 2023 (198) April 2023 (136) March 2023 (142) February 2023 (180) January 2023 (268) December 2022 (135) November 2022 (235) October 2022 (172) September 2022 (160) August 2022 (286) July 2022 (101) Menu Halaman Statis Beranda © 2022 - Html5 Development